![]() ![]() Hi Re: Jorion's Table 6-4, please see tab "Table6-4" of this spreadsheet to see the binomial calcs (I recreated his exhibits to understand myself): of nine or more exceptions can be calculated.'Īnother one, do we need to memorise the Kupiec formula for backtesting or perhaps the more tedious one by Christoffersen? And in the next sentence he says 'the prob. Institutions, 1st Edition) in his examples 8.6 and 8.7 is a bit confusing as well, because he mentions 'we observe nine exceptions while the expected number of exceptions is six'. Your example 60.2 is not quite clear about this as it says 'if the committee increased the green zone from 4 to five exceptions' it does not say whether it is more than 4 exceptions or 4 exceptions or more. Second, is it likely that we need to compute Type I and II errors on the exam? If so, for what 'range' of exceptions? Anything beyond 5 exceptions would be computationally burdensome, right?ĭoes the exam clearly indicate whether they want to see for example: 5 or more exceptions, greater than 5 exceptions? Any ideas how he gets to these values and what they imply? I would be very happy to get either the formula in Excel or the formula for calculation by hand. I would like to address another topic (from a computational perspective as well as from a testable perspective on exam day):įirst, perhaps you can give me a bit of help with this: Jorion in his book 'VaR' gets the values for prob (X = N) in the fifth column of the attached screenshot ( Basel Rules for Backtesting): 0.0 0.4 1.5 3.8 7.2.I tried several BINOMDIST options in Excel, but did not these results. ![]()
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